Close the switch. Zinc atoms at the left electrode give up two electrons each and dissolve into the liquid as Zn2+ ions; at the right electrode Cu2+ ions take two electrons each and settle as copper metal.1,2 Each of those is a half-reaction, and neither can happen alone: each must be coupled, through a cell, to a second half-reaction running the other way.2
The electrons cannot cross the liquid, so they take the wire, from the more negative electrode to the more positive, and the lamp lights on the way.2 Inside the cell the current is carried by ions: cations drift toward the copper and sulfate toward the zinc, so no charge piles up anywhere.1,2
Open the switch and everything stops, but nothing is lost. The voltage you measure with nothing else connected is the open-circuit voltage,1 and a high-impedance voltmeter can read it without drawing any appreciable current.2 For this pair of metals it is 1.10 V: the difference between the standard potentials of the two half-reactions, +0.340 V for copper and −0.763 V for zinc.2
Where a potential sits inside the cell is the strip under the figure: it jumps at each metal|liquid boundary, in a zone so narrow that a very strong field exists there, and stays flat through the liquid; the voltmeter reads the sum of the jumps along the path from one electrode to the other.2
Chapter 3 shows how each jump is built: the chemistry moves a minute charge across the boundary, and the field of that separated charge is what the strip shows.
That is the whole trick, in Goodenough and Park’s words: the electrolyte “conducts the ionic component of the chemical reaction between the anode and the cathode, but it forces the electronic component to traverse an external circuit where it does work”.3
A battery is a chemical reaction that is only allowed to happen through a wire.